Theorem. Let U be an entire function satisfying ∣U(z)∣≤C(1+∣z∣)ke2πR∣Im(z)∣ for some integer k>0. Then U is the Fourier-Laplace transform of a distribution T with compact support on [−R,R].
Proof. Let Vϵ(z)=U(z)Fjϵ(z). Since jϵ is supported on [−ϵ,ϵ], the Paley-Wiener theorem implies that Fjϵ(z) is an entire function satisfying the growth condition that
for every positive integer k. Since U is “moderate increasing”, ∣U(z)∣≤C(1+∣z∣)me2πR∣Im(z)∣ for some integer m>0. Overall, these growth estimates implies that Vϵ(z) satisfies the growth condition of Paley-Wiener theorem for R+ϵ, i.e. ∣Vϵ(z)∣≤Ck′(1+∣z∣)k′e2π(R+ϵ)∣Im(z)∣ for every positive integer k′. The Paley-Wiener theorem implies that Vϵ(z) is the Fourier-Laplace transform of some smooth function vϵ(x) supported on [−(R+ϵ),R+ϵ] and vϵ(x)=F−1Vϵ(x)=F−1U(x)∗F−1Fjϵ(x)=F−1U∗jϵ(x). Note that the identity holds pointwise because they are both smooth functions and equal in sense of distribution (identity principle).
We have showed that supp(F−1U∗jϵ)⊂[−(R+ϵ),R+ϵ]. The support of convolution is equal to the Minkovski sum of supports the convolution elements, so this should imply suppF−1U⊂[−R,R]. To be precise, let T=F−1U, for every φ∈D which is supported outside [−R,R], then eventually for some ϵ>0, suppφ will be outside [−(R+ϵ),R+ϵ] because suppφ is compact, and this implies (T∗jϵ,φ)=0 for small enough ε. In problem set 7 we have showed that T∗jϵ→T weakly, which means limϵ→0(T∗jϵ,φ)→(T,φ). This implies (T,φ)=0 and that suppT⊂[−R,R].